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x^2-x-420=0
We add all the numbers together, and all the variables
x^2-1x-420=0
a = 1; b = -1; c = -420;
Δ = b2-4ac
Δ = -12-4·1·(-420)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-41}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+41}{2*1}=\frac{42}{2} =21 $
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